Write the dual of $p \wedge \sim p \equiv F$
View full solution →Question types
Mathematical Logic question types
47 questions across 4 question groups — pick any mix to generate a Maths paper with step-by-step answer keys.
47
Questions
4
Question groups
5
Question types
01
Answer the following questions in short.
1 Q→02Solve the Following Question.(2 Marks)
22 Q→03Solve the Following Question.(3 Marks)
20 Q→04Solve the Following Question.(4 Marks)
4 Q→Sample Questions
Mathematical Logic questions
One sample from each question group in this chapter. Select any group above to see the full set with answer keys.
Write converse and inverse of the following statement: "If $x>y$ then $x^2>y^{2 }$"
View full solution →$\sim[p \rightarrow(p \wedge \sim q)] \equiv$
- A$p$
- B$q$
- ✓$(p \wedge q)$
- D$(p \vee q)$
Answer: C.
View full solution →If $p \wedge q= F , p \rightarrow q= F$, then the truth value of $p$ and $q$ is :
- AT , T
- BT, F
- CF, T
- DF, F
Using truth table, prove the following logical equivalence : $(p \wedge q) \rightarrow r=p \rightarrow(q \rightarrow r)$
View full solution →Write truth values of the following statements :
(a) $\sqrt{5}$ is an irrational number but $3+\sqrt{5}$ is a complex number.
(b) $\exists n \in N$ such that $n+5>10$.
View full solution →(a) $\sqrt{5}$ is an irrational number but $3+\sqrt{5}$ is a complex number.
(b) $\exists n \in N$ such that $n+5>10$.
Construct the simplified circuit for the following circuit.
Using truth table prove that : $p \leftrightarrow q=(p \wedge q) \vee(\sim p \wedge \sim q)$
View full solution →If $p:$ It is a day time, $q:$ It is warm, write the compound statement in verbal form denoted by -
(a) $p \wedge \sim q$
(b) $\sim p \rightarrow q$
(c) $q \leftrightarrow p$
View full solution →(a) $p \wedge \sim q$
(b) $\sim p \rightarrow q$
(c) $q \leftrightarrow p$
Construct the new switching circuit for the following circuit with only one switch by simplifying the given circuit.
State the converse, inverse and contrapositive of the conditional statement : 'If a sequence is bounded, then it is convergent'.
Examine whether the statement pattern $(\sim p \rightarrow q) \wedge(p \wedge r)$ is a tautology or a contradiction or a contingency.
View full solution →Without using truth table prove that $(p \wedge q) \vee(\sim p \wedge q) \vee(p \wedge \sim q) \equiv p \vee q$
View full solution →Find the symbolic form of the glven switching circuit. Construct its switching table and interpret your result.
Simplify the following circuit so that new circuit has minimum number of switches. Also draw simplified circuit.
Generate a Mathematical Logic paper free
Pick question groups from the list above, set marks and difficulty, and export a branded PDF with step-by-step answer keys. First 3 chapters free — no signup.