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PART - 1 CH - 4 Chemical Bonding and Molecular Structure — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistryPART - 1 CH - 4 Chemical Bonding and Molecular Structure5 Marks
Question
What is hybridization? Describe sp³, sp² and sp hybridization with examples.
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Classify the following reactions in one of the reaction type studied in this unit.
  1. CH3CH2Br + HS- → CH3CH2SH + Br-
  2. (CH3)2 C = CH2 + HCl → (CH3)2 ClC-CH3
  3. CH3CH2Br + HO- → CH=CH2 + H2O + Br-
  4. (CH3)3 C-CH3OH + HBr → (CH3)2 CBrCH2CH2CH + H2O
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Kp = 0.04atm at 899K for the equilibrium shown below. What is the equilibrium concentration of C2H6 when it is placed in a flask at 4.0atm pressure and allowed to come to equilibrium?
$\text{C}_2\text{H}_6(\text{g})\rightleftharpoons\text{C}_2\text{H}_4(\text{g})+\text{H}_2(\text{g})$
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Why is a solution of potassium hydroxide used to absorb carbon dioxide evolved during the estimation of carbon present in an organic compound?
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What is meant by bond order? Calculate bond order of : $N _2, O _2, O _2^{+}$and $O _2^{-}$.
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An element with mass number 81 contains 31.7% more neutrons as compared to protons. Assign the atomic symbol.
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Reaction between $N _2$ and $O _2$ - takes place as follows:
$
2 N_2(g)+O_3(g) \rightleftharpoons 2 N_2 O(g)
$
If a mixture of 0.482 mol of $N _2$ and 0.933 mol of $O _2$ is placed in a 10 L reaction vessel and allowed to form $N _2 O$ at a temperature for which $K_c=2.0 \times 10^{-37}$ determines the composition of the equilibrium mixture.
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Apart from tetrahedral geometry, another possible geometry for CH4 is square planar with the four H atoms at the corners of the square and the C atom at its centre. Explain why CH4 is not square planar?
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Define octet rule. Write its significance and limitations.
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Arrange in properties:
  1. HF, HCI, HBr, HI [Thermal stability]
  2. LiF, LiCI, LiBr, Lil [Ionic character]
  3. PH3, PCI3, PF3, [Covalent character]
  4. H2O, NH3, H2S, HF [Polarity]
  5. BeCl2, BCI3, CCI4, PCI3, [Bond angle]
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Reaction between N2 and O2– takes place as follows:
$\text{2N}_2\text{(g) + O}_2\text{(g)}\rightleftharpoons2\text{N}_2\text{O(g)}$
If a mixture of 0.482mol N2 and 0.933mol of O2 is placed in a 10L reaction vessel and allowed to form N2O at a temperature for which $\text{K}_{\text{c}}=2.0\times10^{-37},$ determine the composition of equilibrium mixture.
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