Question
What is the average binding energy per nucleon over a wide range?
✓
Answer
- 8MeV
The average binding energy per nucleon is just the total binding energy divided by the number of nucleons. If we consider Na atom, its binding energy is 194MeV.
Its binding energy per nucleon is given by $\frac{194\text{MeV}}{24}$
= 8.08MeV
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Pick out the longest wavelength from the following types of radiations(a) Blue light(b) g-rays(c) X-rays (d) Red light
On increasing the reverse bias to a large value in a PN-junction diode, current(a) Increases slowly(b) Remains fixed(c) Suddenly increases(d) Decreases slowly
Consider a wheel of a bicycle rolling on a level road at a linear speed $v_0:$
→
- The speed of the particle $A$ is zero.
- The speed of $B, C$ and $D$ are all equal to $v_0.$
- The speed of $C$ is $2v_0.$
- The speed of $B$ is greater than the speed of $O.$
A bar magnet is released from rest along the axis of a very long, vertical copper tube. After some time the magnet:
If the magnetic flux is expressed in weber, then magnetic induction can be expressed in
A $60$ watt bulb is hung over the center of a table $4 m \times 4 m$ at a height of $3 m$. The ratio of the intensities of illumination at a point on the centre of the edge and on the corner of the table is
→Intensity of light depends upon(a) Velocity(b) Wavelength(c) Amplitude(d) Frequency
Force between the protons and neutrons in a nucleus is:
Two thin lenses whose powers are +2D and –4D respectively combine, then the power of combination is(a) – 2D(b) + 2D(c) – 4D (d) + 4D
A pure semiconductor at absolute zero has: