MCQ
What is the oxidation state of central atom in $\ce{Ca[PtCl_4​]}\ ?$
  • A
    $1$
  • $2$
  • C
    $3$
  • D
    $4$

Answer

Correct option: B.
$2$
$\mathrm{Ca}\left[\mathrm{PtCl}_4\right] \Leftrightarrow \mathrm{Ca}^{+2}[\mathrm{PtCl} 4]^{2-}$
$\text { Take }[\mathrm{PtCl} 4]^{2-} \text {. Central atom }=\mathrm{Pt} \text {. }$
Let $x$ be the oxidation no. of $\ce{Pt},$
$\ce{Cl}$ oxidation no. is $−1.$
$x + 4(−1) = −2$
$x − 4 = −2$
$x = 2$

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