MCQ
What is the $pH$ value of $M\, H_2SO_4$ ?
- A$0$
- B$-0.213$
- C$-2$
- ✓$-0.3010$
$[{H^ + }] = 2$
$pH = - \log [{H^ + }] = - \log \,2$
$ = - 0.3010\,\,\,[\because \,\log \,2 = 0.3010]$
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$aCr _2 O _7^{2-}+ bSO _3^{2-}( aq )+ cH ^{+}( aq ) \rightarrow 2 aCr ^{3+}( aq )+ bSO _4^{2-}( aq )+\frac{ c }{2} H _2 O ( l )$
the coefficients a, b and $c$ are found to be, respectively-
