MCQ
When a particle is thrown vertically upwards, its velocity at one third of its maximum height is $10 \sqrt{2}\,m / s$. The maximum height attained by it is .......... $m$
- A$20 \sqrt{2}$
- B$30$
- ✓$15$
- D$12.8$
$v^2-u^2=-2 g \times \frac{2 H}{3}$
$\Rightarrow-100 \times 2=-2 \times 10 \times \frac{2 H}{3}$
$\Rightarrow H=15 \,m$
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