MCQ
When a proton is accelerated with $1$ volt potential difference, then its kinetic energy is
  • A
    $\frac{1}{1840} eV$
  • B
    $1840\ eV$
  • $1\ eV$
  • D
    $1840 c^2\ eV$

Answer

Correct option: C.
$1\ eV$
$1\ eV$

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