When current supplied by a cell to a circuit is $0.3 \,A$, its terminal potential difference is $0.9 \,V$. When the current supplied becomes $0.25 \,A$, its terminal potential difference becomes $1.0 \,V$. The internal resistance of the cell is ............ $\Omega$
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(b)
$V=E-ir$
$0.9=E-0.3 r$
$1=E-0.25 r$
$0.1=0.05 r$
$r=2 \Omega$
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