- AIt is the ratio of magnetic intensity to intensity of magnetization.
- BThe SI unit of magnetic susceptibility is Tesla (T).
- CIt is the ratio of intensity of magnetization to magnetic intensity.
- DIt is the ratio of magnetic moment to volume.
Explanation:
Magnetic susceptibility of a magnetic substance is defined as the ratio of the intensity of magnetization (I) to the magnetic intensity (H). The expression is given by:
$\text{Xm}=\frac{\text{I}}{\text{H}}$
Magnetic susceptibility measures the aptness of a magnetic substance to acquire magnetism. It is a unit less constant of magnetic substance.
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Eddy currents are produced when
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(a) A metal is kept in varying magnetic field |
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(b) A metal is kept in the steady magnetic field |
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(c) A circular coil is placed in a magnetic field |
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(d) Through a circular coil, current is passed |

The circuit shown in following figure contains two diode D1 and D2 each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 ohm resistance (in amperes) is

| (a) Zero | (b) 0.02 | (c) 0.03 | (d) 0.036 |
A conducting square loop of side l and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A magnetic induction B constant in time and space, pointing perpendicular and into the plane at the loop exists everywhere with half the loop outside the field, as shown in figure. The induced e.m.f. is

|
(a) Zero |
(b) RvB |
(c) VBl/R |
(d) VBl |
An e.m.f. of 12 volt is produced in a coil when the current in it changes at the rate of 45 amp/minute. The inductance of the coil is
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(a) 0.25 henry |
(b) 1.5 henry |
(c) 9.6 henry |
(d) 16.0 henry |
A circular coil of radius 4 cm and of 20 turns carries a current of 3 amperes. It is placed in a magnetic field of intensity of 0.5 . The magnetic dipole moment of the coil is
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(a) 0.15 |
(b) 0.3 |
(c) 0.45 |
(d) 0.6 |
An X-ray tube is operated at 50 kV. The minimum wavelength produced is
| (a) 0.5 Å | (b) 0.75 Å | (c) 0.25 Å | (d) 1 Å |
The depletion layer in silicon diode is 1 mm wide and the knee potential is 0.6 V, then the electric field in the depletion layer will be
|
(a) Zero |
(b) 0.6 Vm–1 |
(c) 6 × 104 V/m |
(d) 6 × 105 V/m |