- AF, Cl, Br, I
- BI, Br, Cl, F
- CBr, Cl, F, I
- DCl, Br, I, F
Explanation:
The bond between carbon and the halogen atom (C-X) is polar. Since halogen atoms are more electronegative than carbon, there is partial negative charge on halogen atom and positive charge on carbon.
This makes the molecule dipolar and polar nature of C-X bond is increase with increase in the electronegativity difference between carbon and halogen atom.
Hence the order of polarity of C−X bond is C−F>C−Cl>C−Br>>C−I.
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$(I)\,\,La(OH)_3$ is the least basic among hydroxides of lanthanides.
$(II) \,\,Zr^{4+}$ and $Hf^{4+}$ posses almost the same ionic radii.
$(III)\,\,Ce^{4+}$ can as an oxidizing agent
Which of the above is/are true ?

${{C}_{6}}{{H}_{5}}OH+CC{{l}_{4}}\underset{(2)\,\,{{H}^{+}}}{\mathop{\xrightarrow{(1)\,\,NaOH}}}\,$