- A$[Ni(NH_3)_6]^{+2}$
- B$[Co(H_2O)_6]^{+2}$
- ✓$[Ti(H_2O)_6]^{+3}$
- D$[Co(NH_3)_6]^{+3}$
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$\mathrm{Sn}(\mathrm{s})\left|\mathrm{Sn}^{2+}(\mathrm{aq}, 1 \mathrm{M}) \| \mathrm{Pb}^{2+}(\mathrm{aq}, 1 \mathrm{M})\right| \mathrm{Pb}(\mathrm{s})$
the ratio $\frac{\left[\mathrm{Sn}^{2+}\right]}{\left[\mathrm{Pb}^{2+}\right]}$ when this cell attains equilibrium is
(Given $\mathrm{E}_{\mathrm{Sn}^{2+} / \mathrm{Sn}}^{0}=-0.14 \mathrm{\;V}$ $\left.\mathrm{E}_{\mathrm{Pb}^{+2}/{\mathrm{Pb}}}^{0}=-0.13 \;\mathrm{V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06\right)$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,}\\
{|\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3} - C - O - C{H_3}}\\
{|\,\,\,\,\,\,\,\,\,\,\,}\\
{\,\,\,\,\,\,\,{\kern 1pt} C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\,\,$ $\xrightarrow[{(1\,Mole)}]{{HI}}$ Products
The main products of reaction will be