Arrange the carbanions, ${\left( {C{H_3}} \right)_3}\bar C,\,\bar CC{l_3},\,{\left( {C{H_3}} \right)_2}\bar CH,\,{C_6}{H_5}\bar C{H_2}$ in order of their decreasing stability
→$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH = C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow{{{\text{D}}Br}}\,Product \,\left( {Major} \right)$ Product will be
→