MCQ
Which of the following circuits correctly represents the following truth table ?
$\begin{array}{*{20}{c}}A&B&C\\0&0&0\\0&1&0\\1&0&1\\1&1&0\end{array}$
- ✓
- B
- C
- D
✓
Answer
Correct option: A.
a
For circuit $1$
For circuit $1$
$A\cdot B\,=\overline{Y\,+\,\overline{A}}\,=\,C$
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