- ✓$Pd$ (atomic no. $= 46$)
- B$Ag$ (atomic no. $= 47$)
- C$Rb$ (atomic no. $= 37$)
- D$Y$ (atomic no. $= 39$)
$\mathrm{Ag}(47):[\mathrm{Kr}] \,5 \mathrm{s}^{1} 4 \mathrm{d}^{10}$
$\mathrm{Rb}(37):|\mathrm{Kr}| \,5 \mathrm{s}^{1}$
$\mathrm{Y}(39):[\mathrm{Kr}] \,5 \mathrm{s}^{2} 4 \mathrm{d}^{1}$
removal of electron is most. difficult from $d^{10}$.
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$CoCl _{3} . xNH _{3}+ AgNO _{3}( aq ) \rightarrow$
If two equivalents of $AgCl$ precipitate out, then the value of $x$ will be $....$
In the above reaction, $3.9\, g$ of benzene on nitration gives $4.92\, g$ of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is............. $\%$. (Round off to the Nearest Integer).
(Given atomic mass: $C : 12.0\, u , H : 1.0\, u$$O : 16.0\, u , N : 14.0\, u )$
