- ✓$Pd$ (atomic no. $= 46$)
- B$Ag$ (atomic no. $= 47$)
- C$Rb$ (atomic no. $= 37$)
- D$Y$ (atomic no. $= 39$)
$\mathrm{Ag}(47):[\mathrm{Kr}] \,5 \mathrm{s}^{1} 4 \mathrm{d}^{10}$
$\mathrm{Rb}(37):|\mathrm{Kr}| \,5 \mathrm{s}^{1}$
$\mathrm{Y}(39):[\mathrm{Kr}] \,5 \mathrm{s}^{2} 4 \mathrm{d}^{1}$
removal of electron is most. difficult from $d^{10}$.
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(Assume $100\%$ ionization)
$A.$ $0.500\,M\,C _2 H _5 OH ( aq )$ and $0.25\, M\, KBr ( aq )$
$B.$ $0.100\,M\,K _4\left[ Fe ( CN )_6\right]$ (aq) and $0.100\, M$ $FeSO _4\left( NH _4\right)_2 SO _4$ (aq)
$C.$ $0.05 \,M\, K _4\left[ Fe ( CN )_6\right]( aq )$ and $0.25\, M\, NaCl$ (aq)
$D.$ $0.15\, M\, NaCl ( aq )$ and $0.1\, M BaCl _2$ (aq)
$E.$ $0.02\, M\, KCl\, MgCl _{2 .} 6 H _2 O ( aq )$ and $0.05\, M$ $KCl ( aq )$

