- AThe intensity decreases in proportion for the distance squared.
- BThe wavefront is parabolic.
- CThe intensity at the wavelength does not depend on the distance.
- DNone of these.
Explanation:
A point source produces a spherical wavefront that moves in all the directions from the point.
Whereas the intensity at the wavelength is dependent on the distance and it follows the inverse square law. So, the intensity decreases with an increase in the distance from the source.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
The half-life of a sample of a radioactive substance is 1 hour. If 8
atoms are present at t = 0, then the number of atoms decayed in the duration t = 2 hour to t = 4 hour will be
|
(a) 2 |
(b) 1.5 |
(c) Zero |
(d) Infinity |
Two long conductors, separated by a distance d carry current I1 and I2 in the same direction. They exert a force F on each other. Now the current in one of them is increased to two times and its directions is reversed. The distance is also increased to 3d. The new value of the force between them is
|
(a) –2F |
(b) F/3 |
(c) 2F/3 |
(d) – F/3 |
There is no couple acting when two bar magnets are placed coaxially separated by a distance because
|
(a) There are no forces on the poles |
|
(b) The forces are parallel and their lines of action do not coincide |
|
(c) The forces are perpendicular to each other |
|
(d) The forces act along the same line |
In a photoelectric experiment for 4000 Å incident radiation, the potential difference to stop the ejection is 2 V. If the incident light is changed to 3000 Å, then the potential required to stop the ejection of electrons will be
|
(a) 2 V |
(b) Less than 2 V |
(c) Zero |
(d) Greater than 2 V |