MCQ
Which of the following is correct
  • A
    Basicity of phosphorous acid is $3$
  • B
    Perchloric acid has one peroxy linkage
  • C
    Trimeta phosphoric acid does not have cyclic structure
  • Borazine has zero dipole moment

Answer

Correct option: D.
Borazine has zero dipole moment
d
$B_3N_3H_6$      $\vec \mu \,\, = \,\,0$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

$CuSO_4(aq) + 4NH_3 \rightarrow X,$ then $X$ is
In which of the following reactions ${H_2}{O_2}$ is a reducing agent
Product $(G)$ is
$17.4\%\, (w/v)$ $K_2SO_4 (Mw=174\,g/mol)$ solution at $27\,^oC$ is isotonic to $4\% \,(w/v)\, NaOH$ solution at same temperature. If $NaOH$ is $100\%$ ionized, what is $\%$ ionization of $K_2SO_4$ in aqueous solution .......... $\%$.
The enthalpies of combustion of $S(s)$ and $H_2(g)$ are $ -300$ and $-290\,\, kcal\,\, mol^{-1.}$ 

Given $SO_3(g) + H_2O(l) \rightarrow H_2SO_4(l)$
$\Delta H = -130\,\, kcal\, mol^{-1}$
$SO_2(g) + 1/2O_2(g) \rightarrow SO_3(g)$
$\Delta H = -100 \,\,kcal\,\, mol^{-1}$
the enthalpy of formation of $H_2SO_4(l)$ would be ......$kcal\, mol^{-1}$

Arrange these compounds in decreasing order of reactivity for the nucleophilic addition reactions

$(I)\,\,HCHO$                                        $ (II)\,\,CH_3CHO$
$(III)$ Acetone                                      $\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {(IV)\,\,\,Et - C - Et} 
\end{array}$

In the given reaction sequence :

$\begin{array}{*{20}{c}}
  {C{H_2} - COOH} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_2} - COOH} 
\end{array}\xrightarrow{\Delta }(A)\xrightarrow{{C{H_3} - C{H_2}N{H_2}/\Delta }}(B)$

$(B)$ will be :

The number of unpaired electrons in $C{r^ + }$ will be
Among the following, the most stable isomer is
For the reaction, $3A+2B \to C + D$, the differential rate law can be written as