MCQ
Which of the following is not a reducing agent
  • A
    $NaN{O_2}$
  • $NaN{O_3}$
  • C
    $HI$
  • D
    $SnC{l_2}$

Answer

Correct option: B.
$NaN{O_3}$
(b) $NaN{O_2}$, $SnC{l_2}$ and $HI$ have reducing and oxidizing properties but $NaN{O_3}$ have only oxidizing property.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Which $C-$atoms is the most electronegative in this structure $\mathop {C{H_3}}\limits^{{\rm{III}}} - \mathop {C{H_2}}\limits^{{\rm{II}}} - C \equiv \mathop {CH}\limits^{\rm{I}} $
Amino acids are produced on hydrolysis of
The number of moles of oxygen in $1\;L$ of air containing $21\%$ oxygen by volume, in standard conditions, is
When ethyl bromide is treated with moist $Ag_2O,$ main product is :
The molar heat of formation of $NH_4NO_3(s)$ is $-367.54\, kJ$ and those of $N_2O(g)$ and $H_2O(l)$ are $+ 81.46 \,kJ$ and $-285.78\, kJ$ respectively at $25\,^oC$ and $1.0$ atmospheric pressure. Calculate $\Delta U$ at $25\,^oC$ for the reaction .....$kJ$

$NH_4NO_3(s) \rightarrow N_2O(g) + 2H_2O(l)$

Given below are two statements: one is labelled as Assertion(A) and the other is labelled as Reason (R).
Assertion(A) : In p-block, when we move down in group, stability of highest oxidation state decreases.
Reason (R) : In d-block, when we move down in group, stability of highest oxidation state increases.
In the light of the above statements, choose the most appropriate answer from the options given below:
In alkaline condition $KMn{O_4},$ reacts as follows :

$2KMn{O_4} + 2KOH \to 2{K_2}Mn{O_4} + {H_2}O + O$

Therefore its equivalent weight will be

How many moles of electrons weigh one kilogram?
$\begin{array}{*{20}{c}}
  {C{H_3}\,\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - C - O - C{H_3}} \\ 
  {\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,} 
\end{array}$ $\xrightarrow[{\left( {Cold} \right)}]{{HI}}$ Product is
The electronic configuration of four elements are

$(I)\,[Kr]\,5s^1$                                  $(II)\, [Rn]\,5f^{14}\,6d^1\,7s^2$ 

$(III)\,[Ar]\,3d^{10}\,4s^2\,4p^5$           $(IV)\,[Ar]\,3d^6\,4s^2$
Consider the following Statements

$(i)\, I$ shows variable oxidation State

$(ii)\, II$ is a $d-block$ element
$(iii)$ The compound formed between $I$ and $III$ is covalent
$(iv)\,IV$ shows single oxidation state
Which Statement is True $(T)$ or False $(F)$?