- ACurium (Z = 96)
- BCalifornium (Z = 98)
- CUranium (Z = 92)
- DTerbium (Z = 65)
Explanation:
Actinoids are elements with Z= 90 - 103. Therefore, Terbium (Z = 65) is not an actinoid. Terbium (Z = 65) is a lanthanoid. $\text{Tb:}\ [\text{xe}]4\text{f}^95\text{d}^06\text{s}^2$
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Compound $(X)$ $\xrightarrow[{Pt}]{{5{H_2}}}$
Compound $(X)$ $\xrightarrow{{AgN{O_3}}}$ Precipitate
Compound $(X)$ $\xrightarrow[{M{e_2}S}]{{{O_3}}}$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,O\,\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{H - C - C{H_2} - C{H_2} - C - C - H}
\end{array}$ $\begin{array}{*{20}{c}}
{\,\,O\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,} \\
{H - C - C - O - H}
\end{array}$ $ + \begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,} \\
{H - C - O - H}
\end{array}$ $ + \begin{array}{*{20}{c}}
{CHO} \\
{|\,\,\,\,\,\,\,\,} \\
{CHO}
\end{array}$
