- A$CO_2$
- B$CH_4$
- ✓$NH_3$
- D$NF_3$
Dipole moment of $CH _4$ is zero because in $CH _4$ the direction of dipole moments are from $H$ to $C$. These dipole moments cancel each other.
In case of $NH _3$, the dipole moment is from $H$ to $N$ and $N$ to lone pair. So it gives a net strong dipole moment of value $1.46 \,D$.
In case of $NF _3$, the dipole moment is from $N$ to $F$ and $N$ to lone pair. These opposite direction dipole moments somehow decreases the value of net dipole moment and gives dipole moment of value $0.46\, D$.
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$I :$ glycerol $II : $ glycol
$III : 1 , 3-$ propenediol $IV :$ methoxy $ -2- $ propanol
