- A$O_2^ - $
- B$NO$
- ✓Both $(a)$ and $(b)$
- D$C{N^ - }$
All the remaining molecules/ions, i.e.,
$C{N^ - }(6 + 7 + 1 = 14)$ diamagnetic
$NO(7 + 8 = 15)$ has odd number of electrons and hence it is paramagnetic.
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(Molar mass of $Fe =56\, g\, mol ^{-1}$ )

| Compound | Weight $\%$ of $P$ | Weight $\%$ of $Q$ |
| $1$ | $50$ | $50$ |
| $2$ | $44.4$ | $55.6$ |
| $3$ | $40$ | $60$ |
$(A)$ If empirical formula of compound $3$ is $P_3 Q_4$, then the empirical formula of compound $2$ is $P_3 Q_5$.
$(B)$ If empirical formula of compound $3$ is $P _3 Q _2$ and atomic weight of element $P$ is $20$ , then the atomic weight of $Q$ is $45$ .
$(C)$ If empirical formula of compound $2$ is $PQ$, then the empirical formula of the compound $1$ is $P _5 Q _4$.
$(D)$ If atomic weight of $P$ and $Q$ are $70$ and $35$ , respectively, then the empirical formula of compound $1$ is $P _2 Q$.