Question
Why europium (II) is more stable than Cerium (II)?
✓
Answer
$Eu ( Z =63)$ Electronic configuration $-[ Xe ] 4 f ^7 5 d^0 6 s^2$
$Eu ^{2+}$ - Electronic configuration Electronic $6 s^1$
$Ce (Z=58)$
Electronic configuration - $[ Xe ] 4 f ^{2+} 5 d^0 6 s^{2+}$
$Ce ^{2+}$ - Electronic confluration $-[ Xe ] 4 f ^2 5 d^0$
According to the Aufbau principle, half-filled and completely filled d (or) forbitals are more stable than partially filled f orbitals.
Hence $Eu ^{2+}[ Xe ] 4 f ^7 5 d^0$ is more stable than $Ce ^{2+}[ Xe ] 4 f ^2 5 d^0$
$Eu ^{2+}$ - Electronic configuration Electronic $6 s^1$
$Ce (Z=58)$
Electronic configuration - $[ Xe ] 4 f ^{2+} 5 d^0 6 s^{2+}$
$Ce ^{2+}$ - Electronic confluration $-[ Xe ] 4 f ^2 5 d^0$
According to the Aufbau principle, half-filled and completely filled d (or) forbitals are more stable than partially filled f orbitals.
Hence $Eu ^{2+}[ Xe ] 4 f ^7 5 d^0$ is more stable than $Ce ^{2+}[ Xe ] 4 f ^2 5 d^0$
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