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Equilibrium — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistryEquilibrium2 Marks
Question
Write the expression for equilibrium constant Kp for the reaction:
$3\text{Fe(s)}+\text{4H}_2\text{O(g)}\rightleftharpoons\text{Fe}_3\text{O}_4(\text{s})+4\text{H}_2(\text{g})$
✓

Answer

$\text{K}_{\text{p}}=\frac{(\text{pH}_2)^4}{(\text{pH}_2\text{O})}$ [Fe and Fe3O4 are pure solids]
[Fe(s)] = [Fe3O4(s)] = 1.

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