MCQ
$X$ compound reacts with $\text{Na}$ to give $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_3$. The compound $X$ is :
- A$ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH} $
- ✓$ \mathrm{CH}_3 \mathrm{CH}_2-\mathrm{Cl} $
- C$ \mathrm{CH}_3-\mathrm{CH}_3 $
- D$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{OH}$
