MCQ
$'x' + H_2O \xrightarrow[{{H_2}S{O_4}}]{{HgS{O_4}}}$ $\begin{array}{*{20}{c}}
  {C{H_3} - C - C{H_2} - C{H_3}} \\ 
  {|\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$ reactant $'x'$ in above reaction is-
  • A
    $CH_3 —CH_2 —C \equiv CH$
  • B
    $CH_3 —C \equiv C — CH_3$
  • C
    $CH_3 — C \equiv CH$
  • Both $(1)$ $\&$ $(2)$

Answer

Correct option: D.
Both $(1)$ $\&$ $(2)$
d
$HgSO_4/H_2SO_4$ is KUCHEROV's Reaction.

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