- A$H^+$ and $XeF_7^-$ ion
- ✓$HF_2^-$ and $XeF_5^+$ ions
- C$HXeF_6^+$ and $F^-$ ions
- Dnone of these
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$I$. $\log \,\,K\, = \,\frac{{nF{E^o}}}{{2.303\,RT}}$
$II$. $K\, = \,{e^{\frac{{nF{E^o}}}{{RT}}}}$
$III$. $\log \,\,K\, = -\,\frac{{nF{E^o}}}{{2.303\,RT}}$
$IV$. $\log \,\,K\, = 0.4342\,\,\frac{{-nF{E^o}}}{{RT}}$
Choose the correct statement $(s)$.

$CH_3-CH_2-OH$ $\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)$ $\xrightarrow{{B{r_2}/KOH}}(C)$
$(C)$ will be :
$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,}\\
{|\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3} - C - O - C{H_3}}\\
{|\,\,\,\,\,\,\,\,\,\,\,}\\
{\,\,\,\,\,\,\,{\kern 1pt} C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\,\,$ $\xrightarrow[{(1\,Mole)}]{{HI}}$ Products
The main products of reaction will be
$(A)$ $\left[\mathrm{Pt}(\mathrm{en}) \mathrm{Cl}_2\right]$ $(B)$ $\left[\mathrm{Pt}(\mathrm{en})_2\right] \mathrm{Cl}_2$
$(C)$ $\left[\mathrm{Pt}(\text { en })_2 \mathrm{Cl}_2\right] \mathrm{Cl}_2$ $(D)$ $\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]$
Mark the correct option
Coordination no. $-$ Oxidation on. $-$ No. of $d-$electrons $-$ Unpaired $d-$electrons