$Y = A \sin \left(\omega t +\phi_{0}\right)$ is the time-displacement equation of a SHM. At $t=0$ the displacement of the particle is $Y =\frac{ A }{2}$ and it is moving along negative $x$ -direction. Then the initial phase angle $\phi_{0}$ will be ...... .
JEE MAIN 2021, Diffcult
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initial phase $\frac{\pi}{2}+\frac{\pi}{3}=\frac{5 \pi}{6}$
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