Method of Preparing Fixture in a Knock-out Tournament.
In a knock-out tournament, the total number of matches can be calculated by subtracting one from the total number of teams. For example, if 8 teams are participating in the tournament, then the number of total matches will be, 8 - 1 = 7. It means that there will be only T matches in the tournament. These teams, i.e., 8 teams should be divided into two halves. It is possible only if the total number of teams is the power of 2 such as 2, 4g, 16, g2 and 64, etc. It is very easy to draw the fixtures in such a case' The total number of teams is divided into equal halves and then matches are decided by draw of lots. If the total number of teams is not the power of 2 such as 3, 5, 6, 7, 9, 10, 11, 12, 13, 14, 15, 17, 18, 19, 20, 21, 22, 23, 24, etc., then byes are given. The teams, which are given byes, do not play in the first round. Byes are given in the first round because of which the number of team playing in the later rounds is reduced to a power of 2. In fact, a bye refers to a dummy team that does not play in the first round but participates in the second round. The number of byes in a fixture is the actual difference between the number of teams participating in the tournament and the next highest number which is the power of 2.
Example 1: How many byes wiII be given if 15 teams are participating in a tournament?
Solution: Total number of teams = 15
Next highest number of power of two = 16
Difference between the total number of teams and the next highest number
in Power of 2 = 16 - 15 =1
Hence, 1 bye will be given.
Example 2: How many byes will be given if 19 teams are participating in a tournament?
Solution: Total number of teams = 19
Next highest number, which is in power of 2 = 32
Difference = 32 - 19 = 13
Hence, 13 byes will be given.