Question types

8. Electromagnetic waves question types

360 questions across 1 question group — pick any mix to generate a Physics paper with step-by-step answer keys.

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Sample Questions

8. Electromagnetic waves questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

A parallel plate capacitor is charged by connecting it to a battery through a resistor. If $l$ is the current in the circuit, then in the gap between the plates:
  • Displacement current of magnitude equal to / flows in the same direction as /
  • B
    Displacement current of magnitude equal to / flows in a direction opposite to that of $I$
  • C
    Displacement current of magnitude greater than / flows but can be in any direction
  • D
    There is no current

Answer: A.

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The property which is not of an electromagnetic wave travelling in free space is that:
  • A
    The energy density in electric field is equal to energy density in magnetic field
  • B
    They travel with a speed equal to $\frac{1}{\sqrt{\mu_0 \varepsilon_0}}$
  • They originate from charges moving with uniform speed
  • D
    They are transverse in nature

Answer: C.

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An ac source is connected to a capacitor $C$. Due to decrease in its operating frequency :
  • A
    capacitive reactance remains constant.
  • B
    capacitive reactance decreases.
  • C
    displacement current increases.
  • displacement current decreases.

Answer: D.

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In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0 \times 10^{10}\,Hz$ and amplitude $48\,Vm ^{-1}$. Then the amplitude of oscillating magnetic field is : (Speed of light in free space $=3 \times 10^8\,m s ^{-1}$)
  • A
    $1.6 \times 10^{-6}\,T$
  • B
    $1.6 \times 10^{-9}\,T$
  • C
    $1.6 \times 10^{-8}\,T$
  • $1.6 \times 10^{-7}\,T$

Answer: D.

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The magnetic field of a plane electromagnetic wave is given by $\overrightarrow{ B }=3 \times 10^{-8} \cos \left(1.6 \times 10^3 x +48 \times 10^{10} t \right) \hat{ j }$, then the associated electric field will be :
  • A
    $3 \times 10^{-8} \cos \left(1.6 \times 10^3 x +48 \times 10^{10} t \right) \hat{ i }\,V / m$
  • B
    $3 \times 10^{-8} \sin \left(1.6 \times 10^3 x +48 \times 10^{10} t \right) \hat{ i }\,V / m$
  • C
    $9 \sin \left(1.6 \times 10^3 x -48 \times 10^{10} t \right) \hat{ k}\,V / m$
  • $9 \cos \left(1.6 \times 10^3 x +48 \times 10^{10} t \right) \hat{ k }\, V / m$

Answer: D.

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