MCQ 11 Mark
Statement-1 (A): There are infinitely many rational numbers between any two integers.
Statement-2 (R):The square of an irrational number is always a rational number.
Statement-2 (R):The square of an irrational number is always a rational number.
- AStatement-1 and Statement-2 are True; Statement-2 is a correct explanation for Statement-5
- BStatement-1 and Statement-2 are True; Statement-2 is not a correct explanation for Statement-1.
- ✓Statement-1 is True, Statement-2 is False.
- DStatement-1 is False, Statement-2 is True.
Answer
View full question & answer→Correct option: C.
Statement-1 is True, Statement-2 is False.
(c)
Between any two integers a and b, there is a rational number $\frac{a+b}{2}$.Between a and $\frac{a+b}{2}$, there is a rational number $\frac{a+\frac{a+b}{2}}{2}$.Continuing in this manner, we can find infinitely many rational numbers between a and b. So, statement-1 is true.
Let $x=\sqrt{\sqrt{3}}$, be an irrational number, then $x^2=\sqrt{3}$ is an irrational number. So, square of an irrational number is not necessarily a. rational number. Thus, statement-2 is not true.
Hence, option (c) is correct.
Between any two integers a and b, there is a rational number $\frac{a+b}{2}$.Between a and $\frac{a+b}{2}$, there is a rational number $\frac{a+\frac{a+b}{2}}{2}$.Continuing in this manner, we can find infinitely many rational numbers between a and b. So, statement-1 is true.
Let $x=\sqrt{\sqrt{3}}$, be an irrational number, then $x^2=\sqrt{3}$ is an irrational number. So, square of an irrational number is not necessarily a. rational number. Thus, statement-2 is not true.
Hence, option (c) is correct.