Maths 3 Marks Question

The equation of given line is x = 4.
This equation does not contain the term of y.
So, the graph of this line parallel to y-axis passing through the point (4, 0).

The equation of given line is x = -2

This equation does not contain the term of y.

So, the graph of this line parallel to y-axis passing through the point (-2, 0).

Given equation:
y = 3x
When x = -2, y = -6
When x = -1, y = -3.
Thus, we have the following table:

x	-2	-1
y	-6	-3

Now plot the point (-2, -6), (-1, -3) on a graph paper.
Join the points and extend the line in both the directions.
The line segment is the required graph of the equation.
From the graph we can that when x = 2, y = 6

Also, when x = -2, y = -6.

The equation of given line is y = 4

This equation does not contain the term of x.

So, the graph of this line parallel to x-axis passing through the point (0, 4).

The equation of given line is y = 3

This equation does not contain the term of x.

So, the graph of this line parallel to x-axis passing through the point (0, 3).

The equation of given line is x + 4 = 0 or x = -4.

This equation does not contain the term of y.

So, the graph of this line parallel to y-axis passing through the point (-4, 0).

The equation of given line is y = -3

This equation does not contain the term of x.

So, the graph of this line parallel to x-axis passing through the point (0, -3).

The equation of given line is x = 5

This equation does not contain the term of y.

So, the graph of this line parallel to y-axis passing through the point (5, 0).

The equation of given line is y + 5 = 0 or y = -5

This equation does not contain the term of x.

So, the graph of this line parallel to x-axis passing through the point (0, -5).