$1.6\, mA$ current is flowing in conducting wire then the number of electrons flowing per second is
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(b) $i = \frac{{ne}}{t}$==> $n = \frac{{it}}{e} = \frac{{1.6 \times {{10}^{ - 3}} \times 1}}{{1.6 \times {{10}^{ - 19}}}} = {10^{16}}$.
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