In the figure the potentiometer wire of length $l =100\, cm$ and resistance $9\Omega$ is joined to a cell of emf $E_1 = 10V$ and internal resistance $r_1 = 1\Omega $. Another cell of emf $E_2 = 5\, V$ and internal resistance $r_2 = 2 \Omega $ is connected as shown. The galvanometer $G$ will show no deflection when the length $AC$ is ............... $cm$
Medium
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$\mathrm{i}_{0}=\frac{10 \mathrm{V}}{10 \Omega}=1 \mathrm{\,A}$
$\mathrm{i}_{0}=\frac{9}{100} \times \ell_{1}=5 \mathrm{\,V}$
$\ell_{1}=\frac{500}{9}=55.55$
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