A $5\ V$ battery with internal resistance $2\,\Omega$ and a $2\,V$ battery with internal resistance ln are connected to a $10\,\Omega$ resistor as shown in the figure.
AIEEE 2008, Medium
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Applying kirchoff's loop law in $A B P_{2} P_{1} A$ we get
$-2 i+5-10 i_{1}=0$ .......$(i)$
Again applying kirchoff's loop law in $P_{2} C D P_{1} P_{2}$ we get,
$10 i_{1}+2-i+i_{1}=0$ .....$(ii)$
From $(i)$ and $(ii)$ $11 i_{1}+2-\left[\frac{5-10 i_{1}}{2}\right]=0 $
${\Rightarrow i_{1}=\frac{1}{32} \text { A from } P_{2} \text { to } P_{1}}$
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