A $6\,\,V$ battery is connected to the terminals of a $3\, m$ long uniform wire having resistance $100\,\Omega $. The difference in potential between two points on the wire separated by a distance of $50\, cm$ will be ............. $V$
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$\phi=\frac{6}{3}$
$\Rightarrow \Delta \mathrm{V}=\frac{6}{3} \times 0.5=1 \mathrm{\,V}$
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