A block of mass $1 \,kg$ attached to a spring is made to oscillate with an initial amplitude of $12\, cm$. After $2\, minutes$ the amplitude decreases to $6\, cm$. Determine the value of the damping constant for this motion. (take In $2=0.693$ )
JEE MAIN 2021, Diffcult
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$A = A _{0} e ^{-\gamma\, t}$
$\ln 2=\frac{ b }{2 m } \times 120$
$\frac{0.693 \times 2 \times 1}{120}= b$
$1.16 \times 10^{-2} \,kg / sec$
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