A body is executing $S.H.M.$ When its displacement from the mean position is $4\, cm$ and $5\, cm$, the corresponding velocity of the body is $10 \,cm/sec$ and $8\, cm/sec$. Then the time period of the body is
AIPMT 1991, Medium
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(c) $v = \omega \sqrt {{a^2} - {y^2}} $
==>$10 = \omega \sqrt {{a^2} - {{(4)}^2}} $ and $8 = \omega \sqrt {{a^2} - {{(5)}^2}} $
On solving $\omega = 2$
==> $\omega = \frac{{2\pi }}{T} = 2$
==> $T = \pi \,sec$
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