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A uniform wire of resistance $R$ is uniformly compressed along its length, until its radius becomes $n$ times the original radius. Now resistance of the wire becomes
In a meter bridge experiment the balance point in obtained if the gaps are closed by $2\,\Omega$ and $3\,\Omega$. A shunt of $x\,\Omega$ is added to $3\,\Omega$ resistor to shift the balancing point by $22.5\,cm$. The value of $X$ is $................$
In potentiometer experiment when $K_1$ is closed balance length is $100\,cm$. Then what will be balancing length when $K_2$ is closed ................ $\mathrm{cm}$
Two cells of $e.m.f.$ $E_1$ and $E_2$ are joined in series and the balancing length of the potentiometer wire is $625$ $cm$. If the terminals of $E_1$ are reversed, the balancing length obtained is $125 \,cm$. Given $E_2 > E_1$, the ratio $E_1: E_2$ will be
A wire of resistance $R_{1}$ is drawn out so that its length is increased by twice of its original length.The ratio of new resistance to original resistance is.
The circuit shown in the figure consists of a battery of $emf$ $\varepsilon = 10 \,V$ ; a capacitor of capacitance $C = 1.0$ $ \mu F$ and three resistor of values $R_1 = 2$ $\Omega$ , $R_2 = 2$ $\Omega$ and $R_3 = 1$ $\Omega$ . Initially the capacitor is completely uncharged and the switch $S$ is open. The switch $S$ is closed at $t = 0.$
A $5\ V$ battery with internal resistance $2\,\Omega$ and a $2\,V$ battery with internal resistance ln are connected to a $10\,\Omega$ resistor as shown in the figure.
Three resistors are connected to form the sides of a triangle $ABC$, the resistance of the sides $AB$, $BC$ and $CA$ are $40\,ohms$, $60\,ohms$ and $100\,ohms$ respectively. The effective resistance between the points $A$ and $B$ in $ohms$ will be