A cell of negligible resistance and $e.m.f.$ $2$ $volts$ is connected to series combination of $2$, $3$ and $5\, ohm$. The potential difference in volts between the terminals of $3\, ohm$ resistance will be
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Current supplied by cell $i = \frac{2}{{2 + 3 + 5}} = \frac{1}{5}\,A$
So potential difference across $3$ will be $V = \frac{{3 \times 1}}{5} = 0.6\,V$
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