MCQ
A cone of base radius $R$ and height $h$ is located in a uniform electric field $\vec E$ parallel to its base. The electric flux entering the cone is
- A$\frac{1}{2}\,EhR$
- ✓$E h R$
- C$2\, E h R$
- D$4\, E h R$
$= E \,(hR)\, cos\, 0^o\, = EhR$
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Reason : $\frac{1}{{{C_p}}} = \frac{1}{{{C_1}}} + \frac{1}{{{C_2}}} + \frac{1}{{{C_3}}}$