A copper wire of diameter $1.02\, mm$ carries a current of $1.7\, amp$. Find the drift  velocity $(v_d)$ of electrons in the wire. Given $n$, number density of electrons in copper $= 8.5 \times 10^{27} /m^3$....................... $mm/sec$
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$\mathrm{I}=1.7 \mathrm{\,A}$

$\mathrm{J}=$ current density

$=\frac{\mathrm{I}}{\pi \mathrm{r}^{2}}=\frac{1.7}{\pi \times\left(0.51 \times 10^{-3}\right)^{2}}=\mathrm{nev}_{\mathrm{d}}$

$=8.5 \times 10^{27} \times\left(1.6 \times 10^{-19}\right) \times v_{d}$

$\therefore $ $\mathrm{v}_{\mathrm{d}}=\frac{1.7}{\pi \times\left(0.51 \times 10^{-3}\right)^{2} \times 8.5 \times 10^{27} \times 1.6 \times 10^{-19}}$

$=1.5 \times 10^{-3} \mathrm{\,m} / \mathrm{sec} .=1.5 \mathrm{\,mm} / \mathrm{sec}$

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