In the given circuit diagram, the currents, ${I_1} = - \,0.3\,A,\,{I_4} = 0.8\,A$ and ${I_5} = 0.4\,A,$ are flowing as shown. The currents $I_2,\,I_3$ and $I_6,$ respectively are
JEE MAIN 2019, Medium
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$\mathrm{I}_{3}+\mathrm{I}_{5}=\mathrm{I}_{4} \quad \Rightarrow \quad \mathrm{I}_{3}=\mathrm{I}_{4}-\mathrm{I}_{5}=0.4\, \mathrm{A}$
$\mathrm{I}_{1}+\mathrm{I}_{2}=\mathrm{I}_{4} \quad \Rightarrow \quad \mathrm{I}_{2}=\mathrm{I}_{4}-\mathrm{I}_{1}=1.1\, \mathrm{A}$
$\mathrm{I}_{3}+\mathrm{I}_{6}=\mathrm{I}_{2}+\mathrm{I}_{1} \Rightarrow \quad \mathrm{I}_{6}=\mathrm{I}_{2}+\mathrm{I}_{1}-\mathrm{I}_{3}=0.4 \,\mathrm{A}$
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