Question
A mass is projected horizontally with a velocity u from a tower. Find the horizontal length it will cover from the foot of the tower?

Answer

If h is the height of the tower, the time taken to reach the ground is $\text{t}=\sqrt{\frac{2\text{h}}{\text{g}}}.$ Since the horizontal velocity u is same everywhere, the distance covered is $\text{ut}=\text{u}\sqrt{\frac{2\text{h}}{\text{g}}}.$

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