A meter bridge is set up as shown, to determine an unknown resistance ' $X$ ' using a standard $10\,ohm$ resistor. The galvanometer shows null point when tapping-key is at $52\,cm$ mark. The endcorrections are $1\,cm$ and $2\,cm$ respectively for the ends $A$ and $B$. The determined value of ' $X$ ' is $..........\Omega$
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$b$
At Null point $\frac{X}{\ell_1}=\frac{10}{\ell_2} \Rightarrow$
$\frac{X}{53}=\frac{10}{50} \quad \therefore X=\frac{53}{5}=10.6 \Omega$
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