A meter bridge setup is shown in the figure. It is used to determine an unknown resistance $R$ using a given resistor of $15\,\Omega$. The galvanometer $(G)$ shows null deflection when tapping key is at $43\,cm$ mark from end $A$. If the end correction for end $A$ is $2\,cm$. then the determined value of $R$ will be__________ $\Omega$
JEE MAIN 2022, Diffcult
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Using the conditions of a balanced wheat stone bridge and adding the end correction.
$\frac{15}{(43+2)}=\frac{R}{(102-45)} \Rightarrow R=\frac{57}{45} \times 15$
$R=19\,\Omega$
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