A meter bridge setup is shown in the figure. It is used to determine an unknown resistance $R$ using a given resistor of $15\,\Omega$. The galvanometer $(G)$ shows null deflection when tapping key is at $43\,cm$ mark from end $A$. If the end correction for end $A$ is $2\,cm$. then the determined value of $R$ will be__________ $\Omega$
JEE MAIN 2022, Diffcult
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1The resistivity of alloys $ = {R_{{\rm{alloy}}}}$; the resistivity of constituent metals ${R_{{\rm{metal}}}}$. Then, usuallyView Solution
- 2An electric fan and a heater are marked as $100\, watt$, $220\, volt$ and $1000\, watt$, $220\, volt$ respectively. The resistance of the heater isView Solution
- 3Shown in the figure below is a meter-bridge set up with null deflection in the galvanometer. The value of the unknown resistor $R$ is ............. $\Omega$View Solution
- 4A cell of internal resistance $r$ is connected across an external resistance $n r$. Then the ratio of the terminal voltage to the emf of the cell isView Solution
- 5Two ideal batteries of emf $V _1$ and $V _2$ and three resistances $R _1, R _2$ and $R _3$ are connected as shown in the figure.View Solution
The current in resistance $R _2$ would be zero if
$(A)$ $V_1=V_2$ and $R_1=R_2=R_3$
$(B)$ $V_1=V_2$ and $R_1=2 R_2=R_3$
$(C)$ $V_1=2 V_2$ and $2 R_1=2 R_2=R_3$
$(D)$ $2 V _1= V _2$ and $2 R _1= R _2= R _3$
- 6Fig. shows rough sketch of meter bridge. $(G)$ deflects zero at length $\ell \, cm$. Now $R_1$ and $R_2$ are interchanged then balancing length increases by $25\, cm$. Find $R_1/R_2$View Solution
- 7View SolutionSpecific resistance of a conductor increases with
- 8The length of a metallic wire is increased by $20 \%$ and its area of cross section is reduced by $4 \%$. The percentage change in resistance of the metallic wire is $.......$View Solution
- 9View SolutionA heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be
- 10In an electric circuit, a cell of certain emf provides a potential difference of $1.25\, {V}$ across a load resistance of $5\, \Omega .$ However, it provides a potential difference of $1\, {V}$ across a load resistance of $2\, \Omega$. The $emf$ of the cell is given by $\frac{x}{10} v$. Then the value of $x$ is ..... .View Solution