A milliammeter of range $10\, mA$ and resistance $9\, \Omega$ is joined in a circuit as shown. The meter gives full-scale deflection for current $I$ when $A$ and $B$ are used as its terminals, i.e., current enters at $A$ and leaves at $B$ ($C$ is left isolated). The value of $I$ is
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$i_{g}=10 m A=0.01 A$

$V_{A}-V_{B}=\left(I-i_{g}\right) 0.1=i_{g}(9+0.9)$

or $I=\frac{10 \times 0.01}{0.1}=1 A$

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