MCQ
A neutral atom has 12 electrons and 13 neutrons. Its mass number is:
- A12
- B4
- C13
- D25
Explanation:
ass = number of electrons/ protones + number of neutrons
= 12 + 13 = 25
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$(i)\,2Fe(s)\, + \,\frac{3}{2}\,{O_2}\,(g)\, \to \,F{e_2}{O_3}\,(s)\,;$ $\Delta {H^\Theta }\, = \ \,-193.4\,kJ$
$(ii)\,Mg(s)\, + \,\,{O_2}\,(g)\, \to \,MgO\,(s)\,;$ $\Delta {H^\Theta }\, = \, - \,140.2\,kJ$
What is $\Delta {H^\Theta }$ of the reaction ?
$3Mg + Fe_2O_3 \to 3MgO + 2Fe$
.......$kJ$
