A particle executes simple harmonic motion along a straight line with an amplitude $A$. The potential energy is maximum when the displacement is
Easy
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Two pendulums differ in lengths by $22\,cm$ . They oscillate at the same place such that one of them makes $15\,oscillations$ and the other makes $18\,oscillations$ during the same time. The lengths (in $cm$ ) of the pendulums areView Solution
- 2A particle of mass $200 \,gm$ executes $S.H.M.$ The restoring force is provided by a spring of force constant $80 \,N / m$. The time period of oscillations is .... $\sec$View Solution
- 3View SolutionResonance is an example of
- 4Two masses $m_1=1 \,kg$ and $m_2=0.5 \,kg$ are suspended together by a massless spring of spring constant $12.5 \,Nm ^{-1}$. When masses are in equilibrium $m_1$ is removed without disturbing the system. New amplitude of oscillation will be .......... $cm$View Solution
- 5A particle performs $SHM$ on $x-$ axis with time period of $0.5\,sec,$ such that it's velocity is zero at $x = -3\,cm$ and at $x = 9\,cm$. It was located at $x = 0$ and moving in negative $'x'$ at $t = 0$. The equation of $SHM$ of the particle isView Solution
- 6A simple pendulum having length $\ell $ is having speed $\sqrt {2g\ell }$ at bottom most point of its trajectory. Its motion will beView Solution
- 7Acceleration of a particle, executing $SHM$, at it’s mean position isView Solution
- 8The amplitude of a particle executing $SHM$ about $O$ is $10\, cm.$ Then :View Solution
- 9View SolutionThe phase difference between displacement and acceleration of a particle in a simple harmonic motlon is
- 10The equation of $SHM$ of a particle is given asView Solution
$2\,\frac{{{d^2}x}}{{d{t^2}}} + 32x = 0$
where $x$ is the displacement from the mean position of rest. The period of its oscillation (in seconds) is