A particle executing simple harmonic motion has an amplitude of $6\, cm$. Its acceleration at a distance of $2 \,cm$ from the mean position is $8\,cm/{s^2}$. The maximum speed of the particle is ... $ cm/s$
Easy
Download our app for free and get started
$A = {\omega ^2}y$
$\omega = \sqrt {A/y} = \sqrt {\frac{8}{2}} = 2\,rad/sec$
Now ${v_{\max }} = a\omega = 6 \times 2 = 12\,cm/sec$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionA particle executes SHM of amplitude A. The distance from the mean position when its's kinetic energy becomes equal to its potential energy is on
- 2A uniform rod of length $L$ and mass $M$ is pivoted at the centre. Its two ends are attached to two springs of equal spring constants $k$. The springs are fixed to rigid supports as shown in the figure, and the rod is free to oscillate in the horizontal plane. The rod is gently pushed through a small angle $\theta$ in one direction and released. The frequency of oscillation isView Solution
- 3A particle performs $SHM$ on $x-$ axis with time period of $0.5\,sec,$ such that it's velocity is zero at $x = -3\,cm$ and at $x = 9\,cm$. It was located at $x = 0$ and moving in negative $'x'$ at $t = 0$. The equation of $SHM$ of the particle isView Solution
- 4A block of mass $m$ attached to massless spring is performing oscillatory motion of amplitude $'A'$ on a frictionless horizontal plane. If half of the mass of the block breaks off when it is passing through its equilibrium point, the amplitude of oscillation for the remaining system become $fA.$ The value of $f$ isView Solution
- 5Two simple harmonic motions, as shown, are at right angles. They are combined to form Lissajous figuresView Solution
$x\left( t \right) = A\,\sin \,\left( {at + \delta } \right)$
$y\left( t \right) = B\,\sin \,\left( {bt} \right)$
Identify the correct match below
- 6The displacement time equation of a particle executing $SHM$ is : $x = A \,sin\,(\omega t + \phi )$. At time $t = 0$ position of the particle is $x = A/2$ and it is moving along negative $x-$ direction. Then the angle $\phi $ can beView Solution
- 7$Assertion :$ The time-period of pendulum, on a satellite orbiting the earth is infinity.View Solution
$Reason :$ Time-period of a pendulum is inversely proportional to $\sqrt g$ - 8Two simple harmonic motions are represented by equations ${y_1} = 4\,\sin \,\left( {10t + \phi } \right)$ and ${y_2} = 5\,\cos \,10\,t$ What is the phase difference between their velocities?View Solution
- 9View SolutionIn forced oscillations, a particle oscillates simple harmonically with frequency equal to
- 10The length of a simple pendulum is increased by $2\%$. Its time period willView Solution